Engineering Equation Solver Ees Cengel Thermo Iso May 2026

v2 = v1 "Final pressure given" P2 = 500 [kPa] T2 = temperature(Fluid$, P=P2, v=v2) u2 = intEnergy(Fluid$, P=P2, v=v2)

R = 0.287 [kJ/kg-K] "Air" T = 300 [K] m = 1 [kg] P1 = 100 [kPa] P2 = 500 [kPa] v1 = R T/P1 v2 = R T/P2 Engineering Equation Solver EES Cengel Thermo Iso

"Isentropic expansion" s2 = s1 h2s = enthalpy(Fluid$, P=P2, s=s2) T2s = temperature(Fluid$, P=P2, s=s2) x2s = quality(Fluid$, P=P2, s=s2) "If in two-phase" v2 = v1 "Final pressure given" P2 =

| Cengel Table | EES function | |--------------|---------------| | Saturated water T | v_f = volume(Water, T=T_sat, x=0) | | Saturated water P | h_g = enthalpy(Water, P=P_sat, x=1) | | Superheated | v = volume(R134a, T=T, P=P) | | Compressed liquid approx | h(T,P) ≈ h_f@T in EES: h = enthalpy(Fluid$, T=T, P=P) (EES corrects) | v=v2) u2 = intEnergy(Fluid$

"Steady-flow compressor work" w_comp_in = h2 - h1 "kJ/kg"

"Isentropic turbine work" W_s = h1 - h2s "kJ/kg"