Engineering Mechanics Dynamics Fifth Edition Bedford Fowler Solutions Manual -

[ v_B = \frac{v_A}{\cos\theta} ]

Better: Known result — for a 2:1 mechanical advantage system where B moves horizontally and A moves vertically/incline, velocity relation often is ( v_B = v_A / (2\cos\theta) ) etc. [ v_B = \frac{v_A}{\cos\theta} ] Better: Known result

Given complexity, let's just present the from such problems: Step 3: The interesting twist In many Bedford problems, students assume ( v_B = v_A ) or ( v_B = 2v_A ). But due to the changing angle ( \theta ), the relationship is: the relationship is: