Oracle 12c Sql Hands-on Assignments Solutions ❲8K❳

SELECT e.first_name, e.last_name, e.salary, e.department_id FROM employees e WHERE e.salary > (SELECT AVG(salary) FROM employees e2 WHERE e2.department_id = e.department_id) ORDER BY e.department_id, e.salary DESC; Problem 5: Fetch the top 5 highest paid employees, but show ties (i.e., if the 5th highest salary is shared by 3 people, show all of them).

12 minutes Introduction Oracle 12c introduced several game-changing features, such as Top-N Row limiting (the FETCH FIRST clause) and improved Visibility into Partitioned Tables . However, the core of database mastery still lies in solving real-world problems. oracle 12c sql hands-on assignments solutions

WHERE TO_CHAR(hire_date, 'YYYY') = '2012'; Find all products in the oe.product_information table whose list price is between $50 and $200, but exclude products where the product name contains the word 'Monitor'. SELECT e

SELECT employee_id, first_name, last_name, hire_date FROM employees WHERE EXTRACT(YEAR FROM hire_date) = 2012 ORDER BY hire_date ASC; You can also use the TO_CHAR method: WHERE TO_CHAR(hire_date, 'YYYY') = '2012'; Find all products

SELECT employee_id, first_name, last_name, hire_date FROM employees ORDER BY hire_date OFFSET 20 ROWS FETCH NEXT 10 ROWS ONLY; Problem 7: Calculate the exact number of months and years each employee has worked as of today's date. Output format: "14 years, 3 months".

SELECT d.department_name, l.city, COUNT(e.employee_id) AS employee_count FROM departments d LEFT JOIN employees e ON d.department_id = e.department_id LEFT JOIN locations l ON d.location_id = l.location_id GROUP BY d.department_name, l.city ORDER BY employee_count DESC; List employees who earn more than the average salary of their own department.

SELECT product_id, product_name, list_price FROM oe.product_information WHERE list_price BETWEEN 50 AND 200 AND UPPER(product_name) NOT LIKE '%MONITOR%'; Problem 3: Show the department name, city, and the number of employees working in that department. Include departments with zero employees.